private java scripts

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private java scripts

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private java scripts private java scripts elementAt(1); x2 = tempFloat.floatValue(); if (Math.round(x1*AppletWidth) == Math.round(x2*AppletWidth)) break; } } private void CutSegments() { int index = 0; float gap; float x1, x2; Float tempFloat1, tempFloat2; int stop = endpoints.size(); for (int i=0; i < stop; i+=2) { CutMiddleThird(index, index+1); index += 4; } } private void CutMiddleThird(int left, int right) { float gap; float x1, x2; Float tempFloat1, tempFloat2; tempFloat1 = (Float) endpoints.

private java scripts elementAt(left); tempFloat2 = (Float) endpoints.elementAt(right); gap = tempFloat2.floatValue() - tempFloat1.floatValue(); x1 = tempFloat1.floatValue() + gap/3.

private java scripts 0f; x2 = tempFloat2.floatValue() - gap/3.0f; endpoints.insertElementAt(new Float(x2), right); endpoints.insertElementAt(new Float(x1), right); }} Compile and load this applet.

private java scripts Is that clearer? Of course this isn't a perfect representation of the middle third set since we have to deal with points of finite size rather than with genuine mathematical points. Depending on how large a window you give your applet, you will probably only see about six to twelve iterations before we need to start working with fractional pixels.Flying LinesThe next example is harder to describe than it is to code. Like Mondrian it runs in an infinite loop but it's a little more than random images. Compile the following code, run it and then look over the code to see if you can understand the algorithm.

private java scripts

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private java scripts